(y^2)+6=y+4

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Solution for (y^2)+6=y+4 equation: 



(y^2)+6=y+4

We move all terms to the left:

(y^2)+6-(y+4)=0

We get rid of parentheses

y^2-y-4+6=0

We add all the numbers together, and all the variables

y^2-1y+2=0

a = 1; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·1·2
Δ = -7
Delta is less than zero, so there is no solution for the equation

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